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alexandr402 [8]
3 years ago
12

Help please!!! Find the value of x. 13 13 X! 24

Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

x = 5 units

Step-by-step explanation:

since it is an isosceles triangle, the perpendicular "x" bisects the base (24) into two units of 12.

using the Pythagorean theorem:

x² = 13² - 12² = 169 - 144 = 25

x = √25 = 5

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[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
NEED HELP QUICK! 20 POINTS!<br><br><br> Use the Law of Sines to find the measure of Angle R:
Troyanec [42]

Answer:

\large\boxed{m\angle R\approx76^o}

Step-by-step explanation:

\dfrac{\sin R}{SQ}=\dfrac{\sin S}{RQ}\\\\\text{We have:}\\\\SQ=32,\ RQ=26,\ S=52^o\to\sin52^o\approx0.788\\\\\text{Substitute:}\\\\\dfrac{\sin R}{32}=\dfrac{0.788}{26}\qquad\text{multiply both sides by 32}\\\\\sin R\approx0.97\to R=\arcsin(0.97)\\\\R\approx76^o

7 0
3 years ago
Can someone plz help me with this problem and plz show work.
motikmotik

Answer:

C

Step-by-step explanation:

y = 2x + 5

the slope (m) of this line is 2 (which can be written as 2/1)

The slope of a perpendicular line is -1/m (the reciprocal of the slope with the opposite sign)

so m = 2/1 => -1/m = - 1/2 = the slope of a line perpendicular to y = 2x + 5

3 0
3 years ago
The table represents a linear function?
Llana [10]
Hello Fantaysias, 

How are you doing? I know this is kind of late, but here goes nothing! Yes, it is a linear equation, you know this because, the input always will result with the same output. Plus, since it has a slope, which is 10 by the way, it also confirms that this is linear! Linear means, that if you put these plots on a line, it will create a straight line! Hope I helped!

Thank you,
Darian D. 
5 0
3 years ago
Read 2 more answers
Solve show all steps what is 7x-28≥-7
Anestetic [448]

Answer:

x≥3

Step-by-step explanation:

7x-28≥-7

Add 28 to each side

7x-28+28≥-7+28

7x≥21

Divide by 7

7x/7≥21/7

x≥3

4 0
3 years ago
Read 2 more answers
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