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Liono4ka [1.6K]
2 years ago
15

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x? (1 point)

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

f(x) = x³ - 2x² - 24x

x³ - 2x² - 24x = 0

x(x² - 2x - 24) = 0

x = 0

x² - 2x - 24 = 0

a = 1, b = -2, c = -24

Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100

x = (-(-2) - 10)/(2 * 1) = -8/2 = -4

x = (-(-2) + 10)/(2 * 1) = 12/2 = 6

Answer: 2)

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Answer:

The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

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From the Linear Algebra, we define the translation of a given point as:

O'(x,y) = O(x,y) + T(x,y) (1)

Where:

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If we know that B(x,y) = (7,-4), C(x,y) = (2,-5) and T(x,y) = (-3,-3), then the translated points are, respectively:

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The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

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