A ball was thrown upward into the air. The height, in feet, of the ball t seconds after it's thrown can be determined by the fol
1 answer:
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Answer:
D. The ball was thrown from an initial height of 3 feet.
Step-by-step explanation:
The generic form of the equation for (vertical) ballistic motion is ...
where g is the acceleration due to gravity, usually approximated as 32 ft/s², v₀ is the initial upward velocity, and h₀ is the initial height.
The given equation matches the situation where the object was launched vertically at the rate of 40 ft/s from a height of 3 ft.
The 3 represents an initial height of 3 feet.
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Surface area is just the area of all these 4 triangles plus the rectangle.
First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together:
First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together: