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Maru [420]
3 years ago
13

Suppose a forklift hoists a container weighing 2670 Netwons up from

Physics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

<h3>12,015Joules</h3>

Explanation:

Work is said to be done when the force applied to an object cause it to move over a distance.

Workdone =  Force * Distance

Given

Force =  2670 N

Distance = 4.5 meters

Substitute the given values

Work done = 2670 * 4.5

Workdone = 12,015Joules

<em>Hence the amount of work done by the forklift is 12,015Joules</em>

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What might common French citizens have liked and disliked about the metric system when it was adopted
Gwar [14]

They would have disliked that they had to relearn how to measure.

5 0
3 years ago
A body is accelerated continuously. What is the form of the graph?
Inga [223]
That depends on what quantity is graphed.

It also depends on what kind of acceleration is taking place ...
continuous change of speed or continuous change of direction.

-- If the graph shows speed vs time, and the acceleration is a change
in speed, then the graph is a connected series of straight-line pieces. 
Each straight piece slopes up if speed is increasing, or down if speed
is decreasing.

-- If the graph shows speed vs time, and the acceleration is a change in
direction only, then the graph is a straight horizontal line, since speed is
constant.

-- If the graph shows direction vs time, and the acceleration is a change
in speed only, then the graph is a straight horizontal line, since direction
is constant.

-- If the graph shows direction vs time, and the acceleration is a change
in direction, then the graph is a connected series of pieces of line. 
Each piece may be straight if the direction is changing at a constant rate,
or curved if the direction is changing at a rate which grows or shrinks. 
Each piece may slope up if the angle that defines the direction is growing,
or may slope down if the angle that defines the direction is decreasing.

-- If the graph shows distance vs time, and the acceleration is a
change in speed, then the graph is a connected series of pieces
of curves.  Each piece curves up if speed is increasing, or down if
speed is decreasing.

-- If the graph shows distance vs time, and the acceleration is a change
in direction only, then the graph is a straight line sloping up, since speed
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6 0
3 years ago
Suppose a car approaches a hill and has an initial speed of 108 km/h at the bottom of the hill. The driver takes her foot off of
Aleks04 [339]

Answer:

a) The car will reach a height of 45.9 m.

b) The amount of thermal energy generated is 173382 J.

c) The magnitude of the force of friction is 417.8 N.  

Explanation:

Hi there!

a) In this problem, we have to use the conservation of energy. The energy conservation theorem states that the energy of a system remains constant. Energy can´t be created nor destroyed, only transformed. In the case of the car, the initial kinetic energy is transformed into potential energy as the car´s height increases while coasting up the hill.

Then, all the initial kinetic energy (KE) will be transformed into potential energy (PE) (only if there is no friction).

The equation of KE is the following:

KE = 1/2 · m · v²

Where:

m = mass of the car.

v = speed of the car.

The equation of PE is the following:

PE = m · g · h

Where:

m = mass of the car.

g = acceleration due to gravity.

h = height at which the car is located.

Since work done by friction is negligible, we can assume that all the initial kinetic energy will be transformed into potential energy. Then:

KE at the bottom of the hill = PE at the top of the hill

1/2 · m · v² = m · g · h

Solving for h:

1/2 · v² / g = h

Let´s convert the speed unit into m/s:

108 km/h · 1000 m/ 1 km · 1 h / 3600 s = 30 m/s

Now, let´s calculate h:

h = 1/2 · (30 m/s)² / 9.8 m/s²

h = 45.9 m

The car will reach a height of 45.9 m.

b) In this case, all the kinetic energy is not transformed into potential energy because some energy is transformed into thermal energy due to friction. The thermal energy generated is equal to the work done by friction. Then:

KE at the bottom of the hill = PE + work done by friction

KE = PE + Wfr  (where Wfr is the work done by friction).

1/2 · m · v² = m · g · h + Wfr

1/2 · m · v² - m · g · h = Wfr

1/2 · 710 kg · (30 m/s)² - 710 kg · 9.8 m/s² · 21 m = Wfr

Wfr = 173382 J

The amount of thermal energy generated is 173382 J.

c) The work done by friction is calculated as follows:

Wfr = Ffr · Δx

Where:

Ffr = friction force.

Δx = traveled distance

Please, see the attached figure to notice that the traveled distance can be calculated by trigonometry using this trigonometric rule of right triangles:

sin angle = opposite side / hypotenuse

In our case:

sin 2.9° = h / Δx

Δx = h / sin 2.9°

Δx = 21 m / sin 2.9° = 415 m

Then, solving for the friction force using the equation of the work done by friction:

Wfr = Ffr · Δx

Wfr / Δx = Ffr

173382 J / 415 m = Ffr

Ffr = 417.8 N

The magnitude of the force of friction is 417.8 N

6 0
3 years ago
What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
olga55 [171]

Answer:

0.08 w

Explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=V_rI_r cosΦ

We have given maximum voltage =8 volt

V_r=\frac{8}{1.414}

power factor =.25

resistance =25Ω

power factor =\frac{R}{Z}

power factor=\frac{25}{Z}

From here Z=100

P=\frac{8}{1.414} ×\frac{v_r}{Z} ×cosΦ

=5.6577×0.05677×0.25

=0.08w

3 0
4 years ago
Name and describe the three quantized particles
padilas [110]

Answer:

The three quantized particles are:

1. Electrons

2. Protons

3. Neutrons

Explanation:

Quantization can be defined as the conversion of a continuous quantity into discrete set of values.

It can also be defined as the concept which says that the particles exist as the smallest finite and discrete value known as quanta which not be divided further.

The three particles include:

1. The electron bound inside an atom have quantized momentum and energy.

2. The proton bound in the inside of a nucleus has energy in the quantized form only.

3. Also the nucleus bound neutron is also a quantized particle.

4 0
3 years ago
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