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NARA [144]
2 years ago
12

William drew a diagram of a box containing a gas for his science project. His drawing is shown.

Physics
1 answer:
Olin [163]2 years ago
7 0
Question? U need a drawing
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A dogsled team is shown pulling a man on a sled. Below the picture is a free body diagram with 4 force vectors. The first vector
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Please, Help!!
Elenna [48]

Let, 1st force = a

2nd force = b

A.T.Q,

a+b = 10

a-b = 6

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Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. one force is 9.0 n, acting due east, an
Zolol [24]
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
 We have then:
 Horizontal = 9-9.2cos (58) = 4.124742769 N.
 Vertical = 9.2sin (58) = 7.802042485 N
 Then, the resulting net force is:
 F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
 Then by definition:
 F = m * a
 Clearing the acceleration:
 a = F / m
 a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
 answer:
 The magnitude of the body's acceleration is
 2.941756275 m / s ^ 2
6 0
3 years ago
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