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Nonamiya [84]
3 years ago
5

You are pushing a 20-kg box along a horizontal floor. Friction acts on the box. When you apply a horizontal force of magnitude 4

8 N, the box moves at a constant velocity. If you increase your horizontal pushing force to 100 N, what is the acceleration of the box?

Physics
2 answers:
LenKa [72]3 years ago
7 0

Answer:

a = 2.6\,\frac{m}{s^{2}}

Explanation:

The first box has the following equation of equilibrium:

\Sigma F = F - f = 0

f = F

f = 48\,N

The coefficient of friction is:

\mu_{k} = \frac{f}{m \cdot g}

\mu_{k} = \frac{48\,N}{(20\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}

\mu_{k} = 0.245

There is a net acceleration, when horizontal pushing force is increased:

\Sigma F = F - f = m\cdot a

a = \frac{F-f}{m}

a = \frac{100\,N-48\,N}{20\,kg}

a = 2.6\,\frac{m}{s^{2}}

9966 [12]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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Answer:

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Explanation:

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