Primary storage refers to your RAM it is internal storage.
Secondary storage is any storage that is not the primary storage that permanently stores data. Examples are hard drive, tape disk drive, floppy disk drive and compact disk drive.
Off-line storage refers to any device that stores data that is not permanently attached to the computer. Example flash drives, The data remains on the storage device and can be connected to a different computer.
The simplified equation is given as Y=A_3A0+A3A0. To draw the circuit diagram using a minimum number of gates we use this equation and the x^2 equation to form the truth table. This is further explained below.
<h3>What is a circuit?</h3>
Generally, a circuit is simply defined as a full circular channel via which electricity travels in electronics. A power flow, terminals, and a drain make up a basic circuit.
In conclusion, The circuit will need 4 inputs to produce 16 combinations in order to determine if the month contains 31 days. At 4 inputs, there are 12 inputs required. the
Hence,we use this information and the x^2 equation to form the truth table
the Equation is given as
Y=A_3A0+A3A0
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Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
Both careers speak to an audience; however, people involved in the performing arts speak only to a live audience.
Explanation:
sorry im late but im not sure
Answer:
ngl why would i know this
Explanation:
