-x+2 > 1
-x+2+x > 1+x .... add x to both sides
2 > 1+x
x+1 < 2
x+1-1 < 2-1 ... subtract 1 from both sides
x < 1
After solving for x, we get x < 1
To graph this, plot an open circle at 1 on the number line and shade to the left of this value. The open circle indicates that 1 is not part of the solution set.
If your teacher requires you to graph this on an xy grid, then draw a vertical line through 1 on the x axis. Make this vertical line a dashed line. Then shade the entire region to the left of this dashed line. Any point in this shaded region will have an x coordinate that is less than 1. The dashed line acts like the open circle. The dashed line tells the reader "any point on this dashed line is not part of the solution set"
Answer:
Which of the following questions allows for variability?
How many students visited the nurse on Monday, September 15, 2014, at your school?
How many free throws can a person make in one minute?
How much money do doctors earn per year?
How tall are the players on the Harlem Globetrotters?
Step-by-step explanation:
HELP IM SRRY
Answer:
12
Step-by-step explanation:
The reciprocal of 6/5 is D. 5/6
Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.
We need to get reciprocal of a fraction when division is performed.
For example: 2 ÷ 1/5
2 may be a whole number but in fraction form it is 2/1.
1st fraction = 2/1
2nd fraction = 1/5
In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.
1/5 ⇒ 5/1
Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10
So, 2 ÷ 1/5 = 10
The sides of the rectangle are:
xy = 39
2x + 2y
Solve by simultaneous equation:
ysquared -17y + 30 = 0
Solution:
The sides are equal to 15 and 2
