Answer:
-4
Step-by-step explanation:
We can find the slope when given two points by using the following
m = (y2-y1)/(x2-x1)
= (-7--19)/(-2 -1)
= (-7+19)/(-2-1)
= 12/-3
=-4
Answer:
x=90
y=45
z=45
ok but i am not sure at all please confirm
Answer:
The answer is 157 1/2 ( ╹▽╹ )
Answer: C) Sometimes positive; sometimes negative
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Explanation:
Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5
Plug this into f(x)
f(x) = x(x+3)(x+1)(x-4)
f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)
f(-0.5) = -0.5(2.5)(0.5)(-4.5)
f(-0.5) = 2.8125
We get a positive value.
This shows that f(x) is positive on the region of -1 < x < 0
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Now pick a value between x = 0 and x = 4. I'll use x = 1
f(x) = x(x+3)(x+1)(x-4)
f(1) = 1(1+3)(1+1)(1-4)
f(1) = 1(4)(2)(-3)
f(1) = -24
Therefore, f(x) is negative on the interval 0 < x < 4
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In short, f(x) is both positive and negative on the interval -1 < x < 4
It's positive when -1 < x < 0
And it's negative when 0 < x < 4
The statement that correctly describes the horizontal asymptote of g(x) is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:
The horizontal asymptote is given as follows:
Hence the correct statement is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
More can be learned about asymptotes at brainly.com/question/16948935
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