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My name is Ann [436]
3 years ago
15

I need all the answers for the whole paper

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
5 0
I'm so sorry could only answer the top table! If it's just patterns I should be right but if it's science then ignore me.

5,700                           5,700,000,000
11,400                         11,400,000,000
17,100                        17,100,000,000
22,800                         22,800,000,000
28,500                        28,500,000,000
Hope that helped and sorry if I'm not correct

You might be interested in
What is the slope of the line that passes through ( 1, -19 ) and ( -2,-7
Lapatulllka [165]

Answer:

-4

Step-by-step explanation:

We can find the slope when given two points by using the following

m = (y2-y1)/(x2-x1)

  = (-7--19)/(-2 -1)

   = (-7+19)/(-2-1)

   = 12/-3

   =-4

3 0
3 years ago
2. Solve for x, y, and z
topjm [15]

Answer:

x=90

y=45

z=45

ok but i am not sure at all please confirm

8 0
3 years ago
Someone plz help T^T
Ulleksa [173]

Answer:

The answer is 157 1/2 ( ╹▽╹ )

5 0
3 years ago
F(x)= x(x+3)(x+1)(x-4) has zeros at x=-3
anygoal [31]

Answer:  C) Sometimes positive; sometimes negative

============================================================

Explanation:

Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5

Plug this into f(x)

f(x) = x(x+3)(x+1)(x-4)

f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)

f(-0.5) = -0.5(2.5)(0.5)(-4.5)

f(-0.5) = 2.8125

We get a positive value.

This shows that f(x) is positive on the region of -1 < x < 0

----------------

Now pick a value between x = 0 and x = 4. I'll use x = 1

f(x) = x(x+3)(x+1)(x-4)

f(1) = 1(1+3)(1+1)(1-4)

f(1) = 1(4)(2)(-3)

f(1) = -24

Therefore, f(x) is negative on the interval 0 < x < 4

----------------

In short, f(x) is both positive and negative on the interval -1 < x < 4

It's positive when -1 < x < 0

And it's negative when 0 < x < 4

4 0
2 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
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