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3 years ago

Hello, can anyone help me with this question?

Physics

1 answer:

scoundrel [369]3 years ago

6 0

I don’t know if I’m right but I think the answer is A.

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PEg=mgh For a mass of 60kg and 10m high

Anuta_ua [19.1K]

Assuming that the gravitational field strength is 10 N/kg, the sum would look like this:
PEg=mgh
=60×10×10
=6000J
However, you will need to check that you are not meant to be using 9.8 N/kg as the gravitational field strength.

3 0

3 years ago

A heavy turntable, used for rotating large objects, is a solid cylindrical wheel that can rotate about its central axle with neg

scoundrel [369]

Answer:

a) $I = 113.014\,kg\cdot m^{2}$ , b) $m = 2075.556\,kg$

Explanation:

a) The turntable has the following physical model by using Newton's laws:

$F \cdot R = I \cdot \alpha$

The moment of inertia is:

$I = \frac{F\cdot R}{\alpha}$

$I = \frac{(300\,N)\cdot(0.33\,m)}{0.876\,\frac{rad}{s^{2}} }$

$I = 113.014\,kg\cdot m^{2}$

b) The moment of inertia for a solid cylinder:

$I = \frac{1}{2}\cdot m \cdot R^{2}$

The mass of the turntable is:

$m = \frac{2 \cdot I}{R^{2}}$

$m = \frac{(2)\cdot (113.014\,kg\cdot m^{2})}{(0.33\,m)^{2}}$

$m = 2075.556\,kg$

8 0

3 years ago

An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucle

shtirl [24]

Answer:

$-9.45\times10^{-16} \text{ J}$

Explanation:

According to Coulomb's law, the force of attraction between two point charges, $q_1$ and $q_2$ , separated by a distance $d$ is given by

$F = k\dfrac{q_1q_2}{d^2}$

$k$ is a constant with a value of $9\times10^9\text{ F/m}$ .

When we substitute the values from the question,

$F = (9\times10^9\text{ F/m})\dfrac{(-1.60\times10^{-19} \text{ C})\times(+1.31\times10^{-17}\text{ C})}{(1.00\times10^{-10}\text{ m})^2} = -1.89\times10^{-6} \text{ N}$

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

$W = F\times r$

$W = (-1.89\times 10^{-6} \text{ N})\times(5.00\times10^{-10}\text{ m}) = -9.45\times10^{-16} \text{ J}$

This is negative because work is done on the electron, not by it.

3 0

3 years ago

Can somebody helppp me pls thank you:)))))

Elena L [17]

The picture is very blurry I wish I could help

6 0

4 years ago

Read 2 more answers

Which of two factors influence the weight of an object due to gravitational pull?

inna [77]

~Hello there!

Your question: Which of two factors influence the weight of an object due to gravitational pull?

Your answer: The mass and the radius of the planet are the two factors that influence the weight of an object due to the gravitational pull

The answer is option A.

Any queries ^?

Happy Studying!

8 0

4 years ago

Read 2 more answers