Answer:
Explanation:
An object in free fall, NOT experiencing parabolic motion, has an equation of
which says:
The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.
For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;
g = 10 m/s/s, and
t = .5sec
+h and
5 = -5(.5)² + h and
5 = -5(.25) + h and
5 = -1.25 + h so
h = 6.25
That's how high the window is above the ground.
Given below the arrangement of loading on the larger boat by two tug boats.
F₁ = 5 N
F₂ = 4 N
Angle between them θ = 90⁰
Resultant between two vectors, 
Substituting

So magnitude of the net force on the block = 6.403 N
F=K*X,
F=M*a
M*a=K*X
2.5*9.81=K*0.0276
24.525=K*0.0276
24.525/0.0276=K
K= 888.6 N/m ---- force constant
assuming 2.5 refers to the new extension, just divide F/ 0.025
to get
981N/m
Answer:
Part a)

Part b)

So this speed is independent of the mass of the rider
Explanation:
Part a)
By force equation on the rider at the position of the hump we can say

now we will have


now we have



Part b)
At the top of the loop if the minimum speed is required so that it remains in contact so we will have

at minimum speed




So this speed is independent of the mass of the rider