It takes approximately 27 days
Answer:
a) f₀ = 3250 Hz
, f₁ = 6500 Hz, b) μ = 0.00100 kg/m
Explanation:
a) For standing waves to occur, waves of equal frequency that travel in opposite directions must be added
In the points where it is fixed there are nodes and in bellies or anti nodes in another symmetrical point
Fundamental wave: node at the ends, a belly (antinode in the center
L = 1 / 2 λ
Extreme node, two bellies L = 2/2 λ
For more bellies L = n / 2 λ
Therefore the equation for the wavelength is
λ = 2 L / n n = 1, 2, 3,…
Let's calculate
λ₁ = 2/1 (2.20)
λ₁ = 4.4 m
λ₂ = 2/2 2.20
λ₂ = 2.20 m
Having the wavelength we can use the relationship of wave speed and wavelength and frequency
v = λ f
v = √ T /μ
v = √ 14.30 / 0.001
v = 14300 m / s
f = v / λ
f₀ = 14300 / 4.4
f₀ = 3250 Hz
f₁ = 14300 / 2.2
f₁ = 6500 Hz
b) linear density is defined as mass per unit length
μ = m / l
μ = 0.0022 / 2.20
μ = 0.001 kg/m
A.
Impulse is calculated through the equation,
I = mΔv
where I is impulse, m is mass and Δv is change is velocity. Substituting the known values,
I = (6 kg)(23 m/s - 6 m/s)
I = 102 kg m/s
<em>Answer: 102 kg m/s</em>
B.
Impulse in this item is calculated by multiplying the force by the time.
I = Force / time = (29 kg m/s²)(7 s) = 203 kg m/s
<em>Answer: 203 kg m/s</em>
C.
To answer this item, we have to multiply the mass and the velocity to get the impulse and divide the answer by the time to get the force.
F = m(v)/t
Substituting,
F = (0.1 kg)(-5.69 m/s)/0.64 s
F = -0.89 N
<em>Answer: -0.89 N</em>
Weight of the 120kg mass object on the moon
It is a fact that the gravity on the Moon is (1/6)th that on the Earth.
Assuming g ≈ 10 m/s² on the earth.
W = m*(g moon) = 120 * (10/6) = 200N.
Weight on moon = 200N.
The object would weigh approximately 200N on the moon.. The force of gravity acting on the object on the moon is the same as the weight of the object on the moon.
We can't find our answer from your options. Regards
Answer:
The answer to your question is: total energy = 30100.4 J
Explanation:
Kinetic energy (KE) is the energy due to the movement of and object, its units are joules (J)
Data
mass = 1280 kg
speed = 4.92 m/s
Force = 509 N
distance = 28.7 m
Formula

Work = Fd
Process
- Calculate Kinetic energy
- Calculate work
- Add both results
KE = 
KE = 15492.1 J
Work = (509)(28.7)
Work = 14608.3 J
Total = 15492.1 + 14608.3
Total energy = 30100.4 J