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3 years ago

Distinguish

Physics

1 answer:

yaroslaw [1]3 years ago

4 0

Answer:

Velocity and speed both are continuously increasing.

Acceleration is constant.

Explanation:

Speed is defined as length of path covered by a body per unit time. Speed is a scalar quantity that consist of magnitude only and not direction.

Velocity is defined as the displacement per unit times. Displacement is the shortest distance between the two points. It is a vector quantity and hence has a direction in the direction of displacement along with its own magnitude.

Both velocity and speed have same unit of measure which is meter per second in S.I. During <em>free fall</em> in the absence of any air resistance the velocity and speed both will be having a vertical downward direction with continuously increasing magnitude. Tough we are not concerned about the direction when discussing about speed but here both are equal since the motion is linear.

Acceleration is the rate of change in velocity of a body which is a vector quantity. For speed we are concerned about instantaneous acceleration since for a short period of time it may have a specific direction.

During free fall the acceleration is of a body is equal to the acceleration due to gravity and constant when the height of fall is much lesser than the radius of the earth.

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A 16.0 cm × 16.0 cm square loop of wire lies in the xy-plane with its bottom edge on the x-axis. The resistance of the loop is 0

Alina [70]

Answer:

the induced current is $I = 3.2768*10^{-4} \ \ A$

Explanation:

Given that :

side of the square (l) = 16 cm = 0.16 m

Magnetic field B = 0.750 y² t

Resistance R = 0.500 Ω

Time t = 0.490 s

Let consider a small rectangular; whose length is $l$ and breath is $dy$

Hence; to determine the magnetic flux through it small rectangular; we have:

$d \phi = B.dA \\ \\ d \phi = B (i * dy) \\ \\ d \phi = (0.750 \ y^2 t ) *(l *dy) \\ \\ d \phi = ( 0.75*t*l) y^2 dy \\ \\ d\phi = (0.75 tl) y^2 dy$

Let calculate the total flux in the square loop

$\phi = \int\limits^{y=l}_{y=0} B.dA \\ \\ \phi = \int\limits^{y=l}_{y=0} (0.75 \ t \ l ) y^2dy \\ \\ \phi = (0.75 \ t \ l )\frac{l^3}{3} \\ \\ \phi = (0.75 \ t )\frac{l^4}{3}$

Thus the total flux in the square loop is $\phi = (0.75 \ t )\frac{l^4}{3}$

Now; going to the induced emf; let consider the Faraday's Law

$V = \frac{d \phi}{dt}$

$V = \frac{d }{dt}(\frac{0.75*l^4}{3})*t$

$V = (\frac{0.75*0.16^4}{3})$

$V = 1.6384*10^{-4} \ V$

Finally ; the induced current I is given by the expression;

$I = \frac{V}{R} \\ \\ I = (\frac{1.6384*10^{-4}}{0.5})$

$I = 3.2768*10^{-4} \ \ A$

Therefore; the induced current is $I = 3.2768*10^{-4} \ \ A$

5 0

3 years ago

Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th

hichkok12 [17]

Answer:

The minimum scale reading during the trip was 560N.

Explanation:

So, in order to solve this problem, we must first prepare a drawing that will represent the situation. (See picture attached)

In the drawing we have the three situations represented. When the elevator goes up, when it travels at a constant velocity and when it decelerates.

We can now do an analysis of each of the situations:

When elevator starts moving:

When the elevator starts moving, it will be accelerated upwards, so the sum of forces will be equal to the mass times the acceleration. In this case, we have two forces, Weight and the normal force, which is the force the floor of the elevator is making upon the scale. This is the reading the scale will give you.

ΣF=ma

-W+N=ma

N=ma+W

As you may see, in this case the weight is added to the force applied by the elevator to accelerate, so the scale reading will be maximum here.

When the elevator has constant velocity:

If the elevator has constant velocity, then its acceleration will be zero, so the sum of the forces will be equal to zero.

ΣF=0

-W+N=0

N=W

On this stage, the scale will return a reading of 800N, since it will not be accelerated.

When the elevator is decelerating:

On the final stage of the trip, the elevator will have a negative acceleration (it is decelerating) so the sum of the forces will be equal to the product between the mass and the acceleration, so we get:

ΣF=-ma

-W+N=-ma

N=W-ma

In this final stage, we can see that the elevator's force is being subtracted from the weight due to the loss of velocity. This is where the scale will give you a minimum reading, so we analyze this stage.

Weight is found by multiplying mass and the acceleration of gravity:

W=mg

so we can rewrite our equation as:

N=mg-ma

when factoring the mass we get:

N=m(g-a)

the mass can be found by dividing the weight into the acceleration of gravity:

W=mg

$m=\frac{W}{g}$

$m=\frac{800N}{10\frac{m}{s^{2}}}$

m=80kg

we know that in the middle of the trip, the elevator will travel 6m in 1s, so the constant velocity is:

$V=\frac{d}{t}$

$V=\frac{6m}{1s}$

$V=6\frac{m}{s}$

this is the initial velocity for the final stage. The acceleration of the final stage can be found with the following formula:

$a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}$

the final velocity is zero since it goes to a stop, so the formula becomes:

$a=\frac{-V_{0}^{2}}{2x}$

when substituting we get:

$a=\frac{-(6m/s)^{2}}{2(6m)}$

$a=-3\frac{m}{s^{2}}$

When substituting values we can now find the scale's reading:

$N=80kg(10m/s^{2}-3m/s^{2})$

$N=80kg(7m/s^{2})$

N=560N

So the minimum scale reading during the trip was 560N

6 0

3 years ago

If you are startled by a sudden loud noise, your (____)

Paraphin [41]

Answer:

D. sympathetic

Explanation:

6 0

3 years ago

Read 2 more answers

During the French and Indian war France and Great Britain fought for control of north American territory what impacted the end o

Marta_Voda [28]

Answer:

during American War, George Washington was voted as a military chef. So USA and France decided to be allies (France lost 7years war so they wanted to revenge to Great Britain).

after revolution

In 1778, Bill of Rights was made after that, every Americans got liberty, New laws with president and their own country (USA).

4 0

3 years ago

If an airplane were traveling eastward with a thrust force 450 N and there was a tailwind of 200 N, what would the resulting net

Alika [10]

The resulting net force is 650N

Explanation:

The force caused by air resistance against the plane's motion is called the Drag force. It acts against the motion of the plane. However, tailwinds push the plane from its tail and they apply a force is the direction of the moving plane.

The resulting force is the sum of the two forces; 450N +200N = 650N

Learn More

Drag and tail force on a plane :brainly.com/question/11922080

Keywords : thrust, force, tailwind, resulting net force

#LearnwithBrainly

4 0

3 years ago