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WARRIOR [948]
2 years ago
14

A stem growing up and out of the soil, away from gravity is an example of a _______.

Biology
1 answer:
Tomtit [17]2 years ago
5 0
<span>A tropism is a movement of an organism toward or away from a stimulus. A positive tropism is when the organism moves toward the stimuli. A negative tropism is when the organism moves away from the stimuli. So, your answer will be negative tropism, since the stem is growing up and out of the soil, AWAY from gravity.</span>
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Questions are in the picture answer both plsss
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Answer:

13. is Option J) all of the above

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3 years ago
Which of the following is an example of an ABAB design? Half of the subjects receive one treatment and the other half are not tr
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Answer:

Option D, A subject is observed both before and after two exposures to the treatment.

Explanation:

In A-B-A-B design the alphabets have following meaning

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b) First B – It is the treatment measurement

c) Second A  - It is the withdrawal of treatment  

d) Second B – It is the reintroduction of treatment  

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4 0
3 years ago
A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

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