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MArishka [77]
3 years ago
14

What is the solution to the equation below? 4(3x + 5) = 5(x + 4) + 7x A infinite solutions OB no solution 0 со D 3​

Mathematics
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

Step-by-step explanation:

here you go mate

step 1

4(3x+5)=5(x+4)+7x  equation

step 2

4(3x+5)=5(x+4)+7x  simplify by distributing

12x+20=12x+20

step 3

12x+20=12x+20  subtract 12x

20=20

step 4

20=20  Divide

0=0

answer

all are real numbers

Alex787 [66]3 years ago
4 0

Answer: All Numbers Are Real Solutions (Note - Have An Amazing Day! :)

Comment If I'm Wrong!

Step-by-step explanation:

4(3x+5)=5(x+4)+7x

4(3x+5)=5(x+4)+7x

(4)(3x)+(4)(5)=(5)(x)+(5)(4)+7x

12x+20=5x+20+7x

12x+20=(5x+7x)+(20)

12x+20=12x+20

12x+20=12x+20

12x+20−12x=12x+20−12x

20=20

20−20=20−20

0=0

Answer:  All real numbers are solutions

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Evaluate the expression when c=2. 6c/2​
marshall27 [118]

Answer:

<h3>6</h3>

Step-by-step explanation:

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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