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V125BC [204]
3 years ago
8

What is the surface area of the cylinder with height 4 yd and radius 7 yd? Round your answer to the nearest thousandth.

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

483.87yd^2

Step-by-step explanation:

Given data

Height= 4yd

Radius= 7yd

The expression for the surface area of a cylinder is given as

Surface area=  2πr (4+ 7)

Surface area= 2*π*7 (4 + 7)

Surface area = 14π (11)

Surface area= 154*3.142

Surface area= 483.87yd^2

Hence the surface area is 483.87yd^2

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The general form of a circle is given as x^2 + y^2 + 4x - 12y + 4 = 0.
stepan [7]
If you can rewrite the formula as (x-a)² + (y-b)² = r², the center is at (a,b) and the radius is r.

If you work out this equation, and map it to the original, you will find that the +4x term hints that a = 2 (double product) and -12y hints that b=-6, and r=6.

So, the formula can be written as (x+2)² + (y-6)² = 6² and the center is at (-2,6) and the radius is 6.
7 0
3 years ago
Find the area of the polygon.
nignag [31]

Answer:

35 sq units

Step-by-step explanation:

4 0
3 years ago
I have two weeks to do 55% of my math and 10% of my english in Edgeenuity, is this do-able?
aleksley [76]

Answer:

Yes , depends on will power .

Step-by-step explanation:

Look , 55% of maths means more than your half of the syllabus . and that too in 2weeks . Sometimes it happens , when you target a very big goal , u end up ignoring small and crucial things . when it comes to learning everyone should be patient and always learn step by step . you ask _ you can do or not ? yes YOU can definitely . but when it comes to understand and analys - "how much that study was helpful" then the answer should be "100% helpful " . but if its not , then what's the need of even studying that ? . At the end of the day we all are studying to learn not to conpelete syllabus .

Am just saying , take your time - go through each chapter , eaxh topic deeply so that it would be helpful in other classes too .

<em>At the end of the day - Quality matters not quantity :)</em>

6 0
3 years ago
HELP ME PLEASE HELP ME HELP ME PLEASE
riadik2000 [5.3K]

Answer:

<h2>     no, because the remainder is 126</h2>

Step-by-step explanation:

if x+3 is a factor, then -3 is a root of expression, and the remainder would be 0

calculating remainder:

-3(-3)^3+6(-3)^2+6(-3)+9=-3\cdot(-27)+6\cdot9-18+9=\\\\=81+54-9=126

4 0
3 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
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