Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
This is a relation but not a function.
Functions must have that there is a unique y for a given x, which clearly doesn't work here because all lines of a given x have 2 y-values. However, it is a relation because there is a given set of points which are defined to be within the set of the ellipse (if it's defined which members of two sets, the range and domain, go together, then you have a relation)
Answer:
x = 1, y = 1
Step-by-step explanation:
3x - 4y = -1
5x + 2y = 7
If we multiply the whole second equation by 2, we get:
10x + 4y = 14
Adding this to the first equation:
10x + 4y + 3x - 4y = 14 - 1
13x = 13
x = 1
Applying this to the second equation:
5 (1) + 2y = 7
2y = 2
y = 1
Slope is -1/2
2-4/6-2=
-1/2
m=-1/2
Point S is located at 2,7.
