Answer:
The answer is below
Step-by-step explanation:
Given that f(x)=x(22-x)
a) f(x)=x(22-x)
f(x + h) = (x + h)(22 - (x + h))
f(x + h) = (x + h)(22 - x - h)
f(x + h) = (22x - x² - xh + 22h - xh - h²)
f(x + h) = (-x² + 22x - h²+ 22h - 2xh)
b) f(x)=x(22-x) = 22x - x²
f(x + h) = (-x² + 22x - h²+ 22h - 2xh)
f(x+h)- f(x) = (-x² + 22x - h²+ 22h - 2xh) - (22x - x²)
f(x+h)- f(x) = -x² + 22x - h²+ 22h - 2xh - 22x + x²
f(x+h)- f(x) = -x² + x² + 22x - 22x - h²+ 22h - 2xh
f(x+h)- f(x) = - h²+ 22h - 2xh
c) f(x+h)- f(x) = - h²+ 22h - 2xh
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