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3 years ago

The following list contains the number of movies That a group of 8 students saw in theaters in the past 12 months.

Mathematics

2 answers:

lord [1]3 years ago

7 0

Answer:

I'm pretty sure its 11

first orginize the numbers in numerical order

second the medj an is the middle numbe, if they are to find the mean of those two only

irinina [24]3 years ago

3 0

Answer:

98=97jewnddfsk

Step-by-step explanation:

bc i said so

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The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of 2 2 . what is the measure of the angle

creativ13 [48]

The correct question is
The hypotenuse and one of the legs of a right triangle form an angle that has a cosine of √2/2 .
What is the measure of the angle?

Let
∅--------> the angle
cos ∅=√2/2
cos ∅=[distance of one of the leg/hypotenuse]
[distance of one of the leg/hypotenuse]=√2/2

I could say that
distance of one of the leg=√2
and
hypotenuse=2
so
applying the Pythagorean theorem
c=hypotenuse=2
a=√2
b=?
c²=a²+b²-------> b²=c²-a²------> b²=2²-(√2)²-----> b²=2-----> b=√2

therefore
if a=b
then
the angle ∅=45°

the answer is the option
b.45 degrees

7 0

3 years ago

What's the unit rate of 2.50 for 5 onces

bulgar [2K]

2.50/5 0.50 an ounce

5 0

3 years ago

In the parallelogram shown in the picture solve for Z

deff fn [24]

In a parallelogram, opposite angles are congruent.

Since angles z and 124° are opposite angles in the parallelogram, they are congruent angles.

Therefore we have:

$z=124°$

5 0

9 months ago

What is 77.2-43.778? what is 2.072 divided by 5.6

Shkiper50 [21]

2.072/5.6= 0.37

77.2- 43.778= 33.422

Hope this helps!

~LENA~

8 0

3 years ago

a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$

So, it will take 2.11 seconds to reach the ground.

6 0

3 years ago