Multiply.

When multiplying two negative integers, what is the sign of the product?

uranmaximum [27]

Answer: positive

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

An investment of $100 is now valued at $149.18 the interest rate is 8% compounded continuously about how long has the money been

deff fn [24]

question: An investment of $100 is now valued at $149.18 the interest rate is 8% per year, compounded continuously about how long has the money been invested

Answer:

5.2 years

Step-by-step explanation:

Applying

A = P(1+R/100)ⁿ.......................... Equation 1

Where A = amount, P = principle, R = rate, n = time.

From the question,

Given: A = $149.18, P = $100, R = 8%

Substitute these values into equation 1 and solve for n

149.18 = 100(1+8/100)ⁿ

149.18/100 = (1+8/100)ⁿ

1.4918 = (1+0.08)ⁿ

1.4918 = (1.08)ⁿ

Taking the Logarithm of both side

Log(1.4918) = Log(1.08)ⁿ

Log(1.4918) = nLog(1.08)

n = Log(1.4918)/Log(1.08)

n = 0.1737/0.0334

n = 5.2 years.

7 0

3 years ago

A rectangular window is topped with a semicircle on top. the height of the rectangular part is 1 more than 3 times its width , w

tensa zangetsu [6.8K]

In general for a rectangle of dimensions w by h and a semicircle of diameter w we get an area:

$A = wh + \frac 1 2 \pi (\frac w 2)^2$

The halfs are because a semicircle is half a circle and a radius is half a diameter.

We're told

$h = 1+ 3w$

Substituting,

$A(w) = w(1+3w) + \frac 1 2 \pi (\frac w 2)^2$

Answer: B

5 0

3 years ago

Use vertical multiplication to find the product of:

Rom4ik [11]

Answer:

$x^6+x^4+4x^3-2x^2-x+3$

Step-by-step explanation:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$x^3+2x+3$ Anything times 1 is that anything.

That is, $(x^3+2x+3) \cdot 1=x^3+2x+3$ .

Now we are going to take the top expression and multiply it to the -x in the second expression. $-x(x^3+2x+3)=-x^4-2x^2-3x$ . We are going to put this product right under our previous product.

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$x^3+2x+3$

$-x^4-2x^2-3x$

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

$x^3+2x+3$

$\times(x^3-x+1)$

---------------------------------

$0x^4+x^3+0x^2+2x+3$

$-x^4+0x^3-2x^2-3x+0$

Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us $x^3(x^3+2x+3)=x^6+2x^4+3x^3$ . (I'm going to put this product underneath our other 2 products):