Simplify 1/3(6x - 15) to 6x - 15/3
6x - 15/3 = 1/2(10x - 4)
Factor out the common term; 3
3(2x - 5)/3 = 1/2(10x - 4)
Cancel out 3
2x - 5 = 1/2(10x - 4)
Simplify 1/2(10x - 4) to 10x - 4/2
2x - 5 = 10x - 4/2
Factor out the common term; 2
2x - 5 = 2(5x - 2)/2
Cancel out 2
2x - 5 = 5x - 2
Subtract 2x from both sides
-5 = 5x - 2 - 2x
Simplify 5x - 2 - 2x to 3x - 2
-5 = 3x - 2
Add 2 to both sides
-5 + 2 = 3x
Simplify -5 + 2 to -3
-3 = 3x
Divide both sides by 3
- 1 = x
Switch sides
<u>x = -1</u>
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
.10 because 1.10 - 1.00 = .10
Answer: $1500.00
Step-by-step explanation:
