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Luke is designing a scale model of a clock tower. The design of the front if the tower is shown below. What will be the area of

Komok [63]

Question:

Luke is designing a scale model of a clock tower. the design of the front of the tower is shown below. what will be the area of the front face of his model?

(a) 2,500 square millimeters

(b) 10,000 square millimeters

(c) 12,500 square millimeters

(c) 15,000 square millimeters

The height of the tower is given as 200 mm and the width of the tower is 50 mm

Answer:

The correct option is;

(b) 10,000 square millimeters

Step-by-step explanation:

With the given dimension of the tower, Te front face of the tower is rectangular in shape.

Therefore, we have;

Area of a rectangle = Base Length × Height

Where:

Base length of the tower = 50 mm

Height of the tower = 200 mm

Therefore, area of the rectangular tower is therefore,

Area of a rectangle tower = Base length of the tower × Height of the tower

= 50 mm × 200 mm = 10000 mm².

Area of a rectangle tower = 10000 mm².

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Read 2 more answers

If the random variable X is normally distributed with a mean of 75 and a standard deviation of 8, then P(X ≥ 75) is:a. 0.500b. 0

drek231 [11]

Answer:

a. 0.5

Step-by-step explanation:

We know that X follows normal distribution with

mean=75

standard deviation=8

$P(X\geq 75)=P(\frac{x-mean}{standard deviation}\geq \frac{75-75}{8})$

$P(X\geq 75)=P(Z\geq 0)$

$P(Z\geq 0)=$ P(0<Z<∞)

The area under the normal curve is 1 and the (0<Z<∞) =0.5 and (-∞<Z<0) =0.5

So, P(0<Z<∞)=0.5

Hence the P(X ≥ 75)=0.5

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