How do I find the average number of particles hitting the surface poer unit area and per unit time with no information?
10 1/2 I am pretty sure its right
Answer:

Step-by-step explanation:
The point P(1,0) and T
are on the unit circle C and the arc length from P to T is x.
Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.
Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be
and the y-coordinate will be
.
So, coordinates of T' are
.
Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)
Well if those are the only 3 options of a segment, then there is a 1/3 chance of landing on A, then a 1/3 chance of landing on B, then a 1/3 chance of landing on C. Multiply the fractions together to get 1/27. However that isn't one of your answers. I'm thinking that the spinner has 4 sections, meaning 1/4 chance of A, then 1/4 chance of B, then 1/4 chance of C. Multiply these together to get 1/64, which is one of your answers. That's my input anyway
Answer:
9 < x
Step-by-step explanation:
5x - 47< 3(12x - 108) – 2
Distribute
5x - 47< 36x - 324 – 2
Combine like terms
5x - 47< 36x-326
Subtract 5x from each side
5x-5x - 47< 36x-5x-326
- 47< 31x-326
Add 326 to each side
326 - 47< 31x-326+326
279 < 31x
Divide by 31 on each side
279/31 < 31x/31
9 < x