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3 years ago

30 Points. i fr need to pass this test i dont feel like taking it again my senior year

Mathematics

2 answers:

Ivenika [448]3 years ago

6 0

That’s hella mainey bru same 0

34kurt3 years ago

6 0

Answer:

3x^3+2x^2+2x+5

Step-by-step explanation:

The answer is A

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Sam needs a web designer. Designer A is offering her services for an initial $450 in addition to $105 per hour. Designer B is of

gogolik [260]

Answer:

After 5 hours the two would charge the same amount of money.

Step-by-step explanation:

Designer A: $450 + ($105/hr)x, where x is the number of hours worked;

Designer B: $725 + ($50/hr)x

Equating these two formulas, we get:

$450 + ($105/hr)x = $725 + ($50/hr)x

Subtracting $450 from both sides: ($55/hr)x = $275

Dividing both sides by $55 yields the number of hours worked:

x = $275/$55 = 5

After 5 hours the two would charge the same amount of money.

6 0

3 years ago

Read 2 more answers

Find the equation of the line . Write in slope intercept form and in standard form. (SHOW YOUR SOLUTION)

AlladinOne [14]

Answer:

1) The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ . The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ . The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) The slope-intercept form of the line is $y = 2\cdot x-7$ . The standard form of the line is $-2\cdot x +y = -7$ .

Step-by-step explanation:

From Analytical Geometry we know that the slope-intercept form of the line is represented by:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the standard form of the line is represented by the following model:

$a\cdot x + b \cdot y = c$ (2)

Where $a$ , $b$ are constant coefficients, dimensionless.

Now we process to resolve each problem:

1) If we know that $m = -5$ and $b = 1$ , then we know that the slope-intercept form of the line is:

$y = -5\cdot x + 1$ (3)

And the standard form is found after some algebraic handling:

$5\cdot x +y = 1$ (4)

The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(1,-2)$ and $(x_{2},y_{2}) = (3,3)$ , then we construct the following system of linear equations:

$m+b= -2$ (5)

$3\cdot m +b = 3$ (6)

The solution of the system is:

$m = \frac{5}{2}$ , $b = -\frac{9}{2}$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x +y = -\frac{9}{2}$

$-5\cdot x +2\cdot y = -9$ (7)

The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(-2,0)$ and $(x_{2},y_{2}) = (0,5)$ , then we construct the following system of linear equations:

$-2\cdot m +b = 0$ (8)

$b = 5$ (9)

The solution of the system is:

$m =\frac{5}{2}$ , $b = 5$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x+y =5$

$-5\cdot x +2\cdot y = 10$ (10)

The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) If we know that $a = 2$ and $b = -7$ , then the standard form of the family of lines is:

$2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$

And the standard form is found after some algebraic handling:

$-7\cdot y = -2\cdot x +c$

$y = \frac{2}{7}\cdot x -\frac{c}{7}$ , $\forall \,c\in\mathbb{R}$ (11)

The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) If we know that $(x,y) = (3,-1)$ and $m = 2$ , then the y-intercept of the line is:

$3\cdot 2 + b = -1$

$b = -7$

Then, the slope-intercept form of the line is $y = 2\cdot x-7$ .

And the standard form is found after some algebraic handling:

$-2\cdot x +y = -7$ (12)

The standard form of the line is $-2\cdot x +y = -7$ .

6 0

3 years ago

What are the x & y values?

Savatey [412]

Answer:

You can insert any number instead of X and y because they are Variables.

6 0

4 years ago

A rectangle has a length of 80 units and a width of 39 units. Find the length of the diagonal.

levacccp [35]

Equation = a² + b² = c²

a = 80
b = 39
c = Diagonal

a² + b² = c²
80² + 39² = c²
6400 + 1521 = c²
c² = 7921
c = √7921
c = 89

Answer = 89 units

6 0

4 years ago

Evaluate j/k -0.2k when j =25 and k = 5

denis-greek [22]

When you have an equation that has variables and you know the value of those variables, just plug it it. So plugging the vaules we get
$\frac{25}{5}-\frac{1}{5}5$
Just evaluating we get 4

5 0

3 years ago

Read 2 more answers