Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
There you go!! Hope it helps
Answer:
dy/dx = -1/
Step-by-step explanation:
y = 1/x
dy/dx = d/dx(1/x)
=> dy/dx = d/dx(
)
=> dy/dx = -
=> dy/dx = -1/
On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.
From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.
Therefore, as we have given m∠JKL = 84 & m∠MKL = 42
and we have to find m∠JKM , we will simply write the equation as follow
m∠JKL = m∠JKM + m∠MKL
Inserting values we get,
84 = m∠JKM + 42
m∠JKM = 42
Hence, angle m∠JKM of the triangle ΔJKL is 42.
Learn more about questions related to triangles and their angles here
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Answer:
0.3 feet
Step-by-step explanation:
2.75(0.8)^x
in which x is the number of bounces after the firts bouce
bouce 12 would mean x=11
2.75(0.8)^11 = 0.2