Please help! what is y+7=-1/7(x+4) in slope intercept form?
1 answer:
We know that
the equation of a line in <span>slope intercept form is--------------> y=mx+b
where
m-----------> is the slope
b-----------> is the y-intercept point when x=0
</span><span>y+7=-1/7(x+4)---------> y+7=(-1/7)x-4/7
</span>y+7=(-1/7)x-4/7------> y=(-1/7)x-4/7-7------> y=(-1/7)x-(53/7)
the answer is
y=(-1/7)x-(53/7)-------------> this is the equation of a line in slope intercept form
m=(-1/7)=-0.14
b=(-53/7)=-7.57
y=-0.14x-7.57
see the attached figure
the equation of a line in <span>slope intercept form is--------------> y=mx+b
where
m-----------> is the slope
b-----------> is the y-intercept point when x=0
</span><span>y+7=-1/7(x+4)---------> y+7=(-1/7)x-4/7
</span>y+7=(-1/7)x-4/7------> y=(-1/7)x-4/7-7------> y=(-1/7)x-(53/7)
the answer is
y=(-1/7)x-(53/7)-------------> this is the equation of a line in slope intercept form
m=(-1/7)=-0.14
b=(-53/7)=-7.57
y=-0.14x-7.57
see the attached figure
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Answer:
Step-by-step explanation:
Let,
Now, us simplify the given differential equation and write it in terms of D,
or,
or,
We have our auxiliary equation:
or,
or,
Therefore our solution is,
and,
Applying the boundary conditions, we get,
Solving them gives us,
Hence,