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Digiron [165]
3 years ago
6

Help in solving this problem​

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

x = 2

The answer is 3

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Factor completely. x2−5x−24
Mandarinka [93]

Answer:

(x-8) (x+3)

Step-by-step explanation:

x^2−5x−24

We need two numbers that multiply to negative 24 and add to negative 5

-8*3 = -24

-8+3 = -5

(x-8) (x+3)

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS<br><br>​
Vladimir [108]

Answer:

A. (0, 60)

B. 15x

Step-by-step explanation:

The initial value is the same as the y-intercept, which is 60 or (0, 60).

The rate of change would be the same as the slope. To find the slope, you do rise/run. You move 15 units up, and 1 to the right. That would be 15x.

Hope this helps!

5 0
3 years ago
I WILL GIVE 30 PTS!!! HELP PLEASEEEE!
Digiron [165]

Answer:

i need to see the first point before the transformation

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the median of 16,94,66,29, and 40
anzhelika [568]
\textbf{Hello Friend}


Step-1 :- Arrange in order

=> 16 , 29 , 40 , 66 , 94


There are 5 numbers , the middle term will be Median .


Here , middle term is = 40 .


\bold{Median:} 40





Hope It helps You. ^_^
7 0
3 years ago
Read 2 more answers
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

3 0
2 years ago
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