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poizon [28]
3 years ago
7

Ben is decorating his home with vases of flowers. He bought glass vases that cost $22 each and ceramic vases that cost $14 each.

The total cost of the vases came to more than $172. Also, Ben bought no more than 10 vases in all.
Which system of inequalities can be used to determine the number of glass vases, x, and the number of ceramic vases, y, that Ben could have bought?
Mathematics
2 answers:
Evgen [1.6K]3 years ago
6 0

Answer:

Step-by-step explanation:

x + y = 10

22x + 14y = 172

-22x - 22y = -220

22x + 14y = 172

-8y = - 48

y = 6 ceramic vases

x + 6 = 10

x = 4 glass vases

Pepsi [2]3 years ago
5 0

Answer:

Step-by-step explanation:

cost of glass vases x=22 $

cost of ceramic vases y=$14

22x+14y >172

or 11x+7y>86

x+y≤10

x   y          11x+7y

1   9            11+63=74

2  8            22+56=78

3  7            33+49=82

4   6           44+42=86

_________________

5   5          55+35=90

6   4          66+28=94

7   3          77+21=98

8  2          88+14=102

9  1          99+7=106

he can buy glass vases in the following combinations .

(x,y)→(5,5),(6,4),(7,3),(8,2),(9,1)

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3 years ago
1000 was invested at 5.5% interest, compounded annually. After sometime the amount had grown to 1550. How long was the money inv
scZoUnD [109]

compound interest equation for annually compounded

A=P(1+r)^t

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4 0
3 years ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

B^3=\frac{240}{2\times 48}

B=1.35 m

H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

3 0
3 years ago
I will mark brainliest and 20 pts
vekshin1

I believe the Surface Area is 37 inches^2 and the Volume is 15 inches^2

6 0
3 years ago
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