Step-by-step explanation:
<u>Using Pythagorus theorem</u> :
(A)


(B)

18/2=ab^2/ab^0
9=b^2
b=3
18=a(3^2)
18=9a
a=2
y=2(3^x)
Move −20-20 to the right side of the equation because it does not contain a variable.−9y+4x=20-9y+4x=20−7y+16x−80=0-7y+16x-80=0Move −80-80 to the right side of the equation because it does not contain a variable.−9y+4x=20-9y+4x=20−7y+16x=80-7y+16x=80Write the system of equations in matrix form.[4−92016−780][4-92016-780]Find the reduced row echelon form of the matrix.Tap for more steps...[105010][105010]Use the result matrix to declare the final solutions to the system of equations.x=5x=5y=0y=0The solution is the set of ordered pairs that makes the system true.(5,0)(5,0)Decompose a solution vector by re-arranging each equation represented in the row-reduced form of the augmented matrix by solving for the dependent variable in each row yields the vector equality.X=[xy]=[50]
<h2>
Answer with explanation:</h2>
We know that a removable discontinuity occurs when:
The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.
Also it is a point on the graph such that it is undefined at that point.
The graph that has a removable discontinuity is attached to the answer.
Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.