The correct answer is 23 and 35.
From the given tabular data,
Volume of water (V) = 50.0 ml
Mass of water (m) = 49.7 g
So, the density of water (ρ) = Mass / Volume
or, = 49.7 g /50.0 ml = 0.994 g / ml
<u>Actual value of the density of water (ρ') = 0.998 g /ml</u>
So, the percentage error in the density of water
= [( actual value - observed value) / actual value ] ×100
or, = [ (0.998 g /ml - 0.994 g / ml ) / 0.998 g /ml ] ×100
or, = 0.4 %
Hence, the required % error in the density of water will 0.4 %.
Answer:
36
Step-by-step explanation:
Answer:52
Step-by-step explanation:you just have to add the angles 66 and 62 which will give you 128 which you will subtract from 180 degrees which is the sum of all the angles in every triangle and you will get your answer 52
