Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.
1 answer:
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Answer: y = x + 1
Step-by-step explanation:
First, we will find the slope. The slope of perpendicular lines are negative reciprocals.
In this case, the first slope is 2. The negative of 2 is -2, and the reciprocal of -2 is .
Now, we will plug in this new slope, the point given, and solve for the <em>b</em>, or the y-intercept.
y = <em>m</em>x + <em>b</em>
(-1) = ()(4) + <em>b</em>
-1 = -2 + <em>b</em>
1 = <em>b</em>
Lastly, we will write our equation.
y = <em>m</em>x + <em>b</em>
y = x + 1
The line is y = x + 1, or y = 1 -
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