The product of 7 and p
2 answers:
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Hi <span>Spor7tdardLamilokab, this particular equation is a binomial probability equation:
P(X) = </span>
* 
*
Note that it's not n / k, but rather the notation is n choose k. Brainly software will not allow me to do this, but imagine the n choose k, without the bar, and that the correct notation.
Where
equals 
, where n! is n * (n-1) * (n-2) 8 ... 1
So for your particular equation:
You would repeat the above equation for 4 as well and add that to the computation for 3, since you want the probability that you'll get 3 or more heads.
Solving this produces the answer:
P(x
3) = 0.34308352
You can also solve this with a TI 83 or 84.
To do this, the steps are 2ND | VARS (or DISTR) | BINOMPDF| TRIALS | PROBABILITY | X VALUE
Doing this for 3 and 4 produces the same result:
binompdf(4, 0.52, 3) + binompdf(4, 0.52, 4) = 0.34308352
P(X) = </span>
Note that it's not n / k, but rather the notation is n choose k. Brainly software will not allow me to do this, but imagine the n choose k, without the bar, and that the correct notation.
Where
So for your particular equation:
You would repeat the above equation for 4 as well and add that to the computation for 3, since you want the probability that you'll get 3 or more heads.
Solving this produces the answer:
P(x
You can also solve this with a TI 83 or 84.
To do this, the steps are 2ND | VARS (or DISTR) | BINOMPDF| TRIALS | PROBABILITY | X VALUE
Doing this for 3 and 4 produces the same result:
binompdf(4, 0.52, 3) + binompdf(4, 0.52, 4) = 0.34308352