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Leona [35]
3 years ago
11

Brainliest for correct answer.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

a

Step-by-step explanation:

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The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)
Musya8 [376]

Answer:

y + 2 = \frac{2}{3}(x - 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = \frac{2}{3}(x - 3) ← is in point- slope form

with slope m = \frac{2}{3}

Parallel lines have equal slopes, thus equation of parallel line

with m = \frac{2}{3} and (a, b) = Q(1, - 2) is

y - (- 2) = \frac{2}{3}(x - 1) , that is

y + 2 = \frac{2}{3}(x - 1)

7 0
4 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
A second-order linear differential equation for y(t) is said to be homogeneous if... every term involve either y or its derivati
swat32

Answer: Hello!

A second order differential equation has the next shape:

y''(t) + p(t)y'(t) + q(t)y(t) = g(t)

where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.

And is called homogeneus when g(t) = 0, so you have:

y''(t) + p(t)y'(t) + q(t)y(t) = 0

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.

4 0
3 years ago
Write explicit formula for a1=3, r=-2; then generate 1st 5 terms
Crazy boy [7]

Answer:

  • an = 3(-2)^(n-1)
  • 3, -6, 12, -24, 48

Step-by-step explanation:

These variable names, a1, r, are commonly used in relationship to geometric sequences. We assume you want the terms of a geometric sequence with these characteristics.

a1 is the first term. r is the ratio between terms, so is the factor to find the next term from the previous one.

  a1 = 3  (given)

  a2 = a1×r = 3×(-2) = -6

  a3 = a2×r = (-6)(-2) = 12

  a4 = a3×r = (12)(-2) = -24

  a5 = a4×r = (-24)(-2) = 48

The first 5 terms are 3, -6, 12, -24, 48.

__

The explicit formula for the terms of a geometric sequence is ...

  an = a1×r^(n -1)

Using the given values of a1 and r, the explicit formula for this sequence is ...

  an = 3(-2)^(n -1)

6 0
3 years ago
A student factors 15c2 + c – 28 to the following.
Mamont248 [21]

Answer:

C. The expression is not equivalent, but it is completely factored.

7 0
3 years ago
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