$\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
g(x)=x-3\\
\end{cases}
\\\\\\
\textit{now, one probability is }x^2-1
\\\\\\
f(x)=x^2-1\implies f(~~g(x)~~)=(x-3)^2-1
\\\\\\
f(~~g(x)~~)=(x^2-6x+9)-1\implies f(~~g(x)~~)=x^2-6x+8$

5 0

3 years ago

How many zeros are in the product (6•5)•10

ASHA 777 [7]

There are 2 zeros in the product.
6*5=30
30*10=300
2 zeros

6 0

3 years ago

Read 2 more answers

Write an inequality for the following statement:

MAVERICK [17]

Answer:

1. x ≤ 400

2. x ≥ 200

3. x < 20

Step-by-step explanation:

I am pretty sure that this is right. :)

6 0

2 years ago

Originally the dimensions of a rectangle were 20cm by 23cm. When both dimensions were decreased by the same amount, the area of

SIZIF [17.4K]

The answer is 17cm by 20cm.
The original area is 460cm (20x23), minus 120cm gives a new area of 340cm.
20cm-3cm=17cm and 23cm-3cm=20cm
17cmx20cm = 340cm

6 0

3 years ago