The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
Read more about congruent triangles at:
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<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
16 ounces in a pound.
24 oz= 1.5 ibs.
Added to 10 ibs.
Now has 11.5 ibs.
R(x)= 11.5 - x
The answer to #1 is D.
The answers to #2 is B,C,D,F.. I'm not sure what the remainder of G says..
(2,8) and (-2,10)
<u>y₂</u><u> </u><u>- y₁</u> used to find the slope<u>
</u>x₂ - x₁
<u>
</u>plug in the coordinates
<u>10-8</u> = <u>2</u> all equals -1/2
-2-2 = -4 m=-1/2
<u>
</u>plug one of the coordinates and the slope into y=mx+b, and solve
<u />8=-1/2(2)+b
8=-1+b
9=b
Final Answer: y = -1/2x + 9
