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Snowcat [4.5K]
3 years ago
11

Find the standard deviation of the sample data set.

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

jeka57 [31]3 years ago
4 0

Answer:

Option A)  4.4 is the correct standard deviation of the the given data set.

Step-by-step explanation:

We are given the following data set:

127, 135, 128, 131, 133, 127, 122

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Solving:

Mean =\displaystyle\frac{903}{7} = 129

Sum of squares of differences = 4 + 36 + 1 + 4 + 16 + 4 + 49 = 114

S.D = \sqrt{\frac{114}{6}} = 4.358898944 \approx 4.4

Option A) is the correct standard deviation of the the given data set.

 

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Which ratios are equivalent to 3 parts silver paint to 4 parts green paint?
mestny [16]

The ratio would be 3:4, or however you write ratios.

Hope this helped! :)

6 0
3 years ago
Read 2 more answers
A rectangular swimming pool measures 50 meters in length and 25 meters in width. If the length in the scale drawing is 10 cm, wh
mash [69]

Answer:

The 25 m width of the actual swimming pool in the scale drawing is 5 cm

Step-by-step explanation:

The dimensions of the actual swimming pool given are

Length = 50 meters

Width = 25 meters

The length of the swimming pool on the scale drawing = 10 cm

The scale of the scale drawing is therefore;

10 cm on the scale drawing is equivalent to 50 meters of the actual swimming pool

Which gives;

10 cm:50 m

However, 50 m = 5,000 cm, therefore;

10 cm:5,000 cm or 10 : 5,000

Which is 10 to 5000 or 10/10 to 5000/10 = 1 to 500

The scale of the scale drawing is 1 to 500

or 1 cm of the scale drawing = 5 meters of the actual swimming pool

Therefore, the width of 25 meters of the actual swimming pool can be given as follows;

5 m = 1 cm

1 m = 1 cm/5

25 m = 25× 1 m = 25 × 1 cm/5 = 5 cm

Therefore, the 25 m width of the actual swimming pool in the scale drawing = 5 cm.

5 0
3 years ago
Mila buys 1112 pound of almonds and 56 pound of pecans.
AleksandrR [38]

Answer:

THIS MAKES NO SENCE

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The sum of the digits of
liberstina [14]

Answer:

37

Step-by-step explanation:

3 + 7 = 10

73 - 37 = 36

3 0
2 years ago
For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exerc
raketka [301]

Answer:

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

Step-by-step explanation:

1) The hypotheses are

H0: u1 ≤ u2 against the claim Ha: u1 > u2

The men spend less or equal time than the women  at the gym each week

vs

the men  spend greater time  than the women at the gym each week

2) The test statistic is

t= (x1`- x2`) / √ s1²/n1+ s2²/n2

t= 65.7- 64.8/√(13.9)²/75 + (9.6)²/68

t= 0.9/√2.57613 +1.35529

t=0.4539

and the degrees of freedom is

3) υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

=[(13.9)²/75 + (9.6)²/68]²/ [(13.9)²/75 ]² /74 + [ (9.6)²/68]²/67

= 139

The degrees of freedom is always rounded in this calculation

4) The Critical region is [1.656, ∞]

5) t-score is outside of the critical region, so there is not enough evidence to reject H₀.

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

4 0
2 years ago
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