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Snowcat [4.5K]
3 years ago
11

Find the standard deviation of the sample data set.

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

jeka57 [31]3 years ago
4 0

Answer:

Option A)  4.4 is the correct standard deviation of the the given data set.

Step-by-step explanation:

We are given the following data set:

127, 135, 128, 131, 133, 127, 122

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Solving:

Mean =\displaystyle\frac{903}{7} = 129

Sum of squares of differences = 4 + 36 + 1 + 4 + 16 + 4 + 49 = 114

S.D = \sqrt{\frac{114}{6}} = 4.358898944 \approx 4.4

Option A) is the correct standard deviation of the the given data set.

 

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Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
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The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

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