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3 years ago

PLEASE HELP

Mathematics

1 answer:

Kipish [7]3 years ago

3 0

Answer:

yes tax is .7 per dollar there for every dollar u spend u pay an extra .7

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11. Find the average rate of change of the equation y = x2 + 4x + 1 on the interval -1 < x < 4.

coldgirl [10]

Answer:

31/5

Step-by-step explanation:

[f(4) - f(-1)] / 4-(-1)

7 0

2 years ago

Geometry Please Help.. (22 points)

WINSTONCH [101]

Good luck my G. I gotta answer 2 questions so I can post pics of my test

8 0

3 years ago

Nicole is cooking pancakes. The recipe calls for 4 1/3 cups of milk. She accidentally put in 4 3/4 cups . How many extra cups di

Ugo [173]

4 3/4 - 4 1/3

= 4 9/12 - 4 4/12

= 5/12 <==== extra cup put in

3 0

3 years ago

Read 2 more answers

Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul

o-na [289]

Answer:

H0:p= 0.80 H1: p< 0.80 one tailed test

Step-by-step explanation:

We state the null and alternative hypotheses as that the results are 80 % against the claim that the results are less than 80%.

H0:p= 0.80 H1: p< 0.80 one tailed test

p2= 0.8 , p1= 74/97= 0.763

q1= 1-0.763= 0.237 q2= 0.2

The level of significance is 0.05 .

The Z∝= ±1.645 for ∝= 0.05

The test statistic used here is

Z= p1-p2/ √pq/n

Putting the values:

Z= 0.763 -0.8 / √ 0.8*0.2/97

z= -0.037/ 0.0406

z= -0.9113

The Z∝ = ±1.645 for ∝= 0.05 for one tailed test.

As the calculated value does not fall in the critical region we fail to reject the null hypothesis. There is not sufficient evidence to support the claim that such polygraph results are correct less than 80% of the time.

Using the normal probability table.

P (Z < -0.9113)= 1- P(z= 0.9311) = 1- 0.8238= 0.1762

If P- value is smaller than the significance level reject H0.

0.1762> 0.005 Fail to reject H0.

8 0

3 years ago

What are the roots to<br> the equation<br> 2x² + 6x-1=0?

lys-0071 [83]

Answer:

The roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = $\frac{ - b}{a}$

And products of roots = $\frac{c}{a}$

So, m + n = $\frac{ - 6}{2}$ = - 3

And m × n = $\frac{ - 1}{2}$

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 ( $\frac{ - 1}{2}$ )

Or, (m - n)² = 9 + 2 = 11

I.e m - n = $\sqrt{11}$

Again m + n = - 3 And m - n = $\sqrt{11}$

Solving this two equation

(m + n) + ( m - n) = - 3 + $\sqrt{11}$

I.e 2 m = - 3 + $\sqrt{11}$

Or, m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$

Similarly n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Hence the roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$ Answer

6 0

3 years ago