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liq [111]
3 years ago
12

Find tan A and tan B.

Mathematics
1 answer:
Alex3 years ago
8 0

Step-by-step explanation:

\tan(a)  =  \frac{26}{10}  = 2.6 \\  \tan(b)  =  \frac{10}{26}

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Criminal investigators use biometric matching for fingerprint recognition, facial recognition, and iris recognition. When matchi
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Answer:

It is not a Type I error neither a Type II error.

Step-by-step explanation:

Let \mu be the true mean match score. The null hypothesis is H_{0}: \mu = 80 and the alternative hypothesis is H_{1}: \mu > 80 (upper-tail alternative). When the test shows that the mean match score is more than 80 when actually is equal to 80 a Type I error is made. On the other hand, when the test shows that the mean match score is equal to 80 when actually is more than 80 a type II error is made. Therefore, when the test shows that the mean match score is more than 80 when the person does not actually have a fingerprint match, does not correspond to a Type I error neither to a Type II error.

6 0
3 years ago
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Artyom0805 [142]
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Step-by-step explanation:

easy

8 0
3 years ago
Given the polynomail function below, find f(-5) f(x)=x^2-2x-7
SIZIF [17.4K]
F(-5) = -5^2 - 2*(-5) - 7 = 25 - (-10) - 7 = 25 + 10 - 7 = 25 + 3 = 28
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