Answer: What are the options for the functions?
Step-by-step explanation:
Answer:
10x-1y
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14
b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5
c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16
d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16
e) cannot decipher the equation
f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21
First day: 25% × 100 = 25 ( miles)
Second day : the remaining distance is 100 - 25 = 75 ( milesl
Third day: 40% × 75 = 30
25 + 75 + 30 = 130 (miles)
Check the picture below.
now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer. That matters because the derivative of a constant is zero.
now, those are the values when the rocket is 30 feet up above.
![\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y \\\\\\ \stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt} \\\\\\ \boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\ -------------------------------\\\\ ](https://tex.z-dn.net/?f=%5Cbf%20tan%28%5Ctheta%20%29%3D%5Ccfrac%7By%7D%7Bx%7D%5Cimplies%20tan%28%5Ctheta%20%29%3D%5Ccfrac%7By%7D%7B15%7D%5Cimplies%20tan%28%5Ctheta%20%29%3D%5Ccfrac%7B1%7D%7B15%7D%5Ccdot%20y%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7Bchain~rule%7D%7Bsec%5E2%28%5Ctheta%20%29%5Ccfrac%7Bd%5Ctheta%20%7D%7Bdt%7D%7D%3D%5Ccfrac%7B1%7D%7B15%7D%5Ccdot%20%5Ccfrac%7Bdy%7D%7Bdt%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Bcos%5E2%28%5Ctheta%20%29%7D%5Ccdot%5Ccfrac%7Bd%5Ctheta%20%7D%7Bdt%7D%3D%5Ccfrac%7B1%7D%7B15%7D%5Ccdot%20%5Ccfrac%7Bdy%7D%7Bdt%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B%5Ccfrac%7Bd%5Ctheta%20%7D%7Bdt%7D%3D%5Ccfrac%7Bcos%5E2%28%5Ctheta%20%29%5Cfrac%7Bdy%7D%7Bdt%7D%7D%7B15%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A)