Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
<h2><em>Answer:</em></h2><h2><em>3×7-2×6+3</em></h2><h2 /><h2><em>=21-12+3=24-12</em><em>=</em><em>1</em><em>2</em></h2><h2 />
Answer:
C
Step-by-step explanation:
the sum of complementary angles = 90°, hence
x + 5 + x - 9 = 90
2x - 4 = 90 ( add 4 to both sides )
2x = 94 ( divide both sides by 2 )
x = 47
Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°
The pattern is to divide by 3
486 ÷ 3 = 162
162 ÷ 3 = 54
54 ÷ 3 = 18
18 ÷ 3 = 6
The next number is 6
