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3 years ago

5

I need help with these two please and thank you

1 answer:

Stells [14]3 years ago

4 0

Answer:

Question 3: A: 628.32

Question 4: C: 2,854.14

Step-by-step explanation:

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Determine the average rate of change for the graphs below!

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The atajan of that wheat of the graph is lowland of the quake

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3 years ago

Simplify 2√2-√3<br> ---------------<br> √2+√3

serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

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6 0

2 years ago

What is the equation of line perpendicular to y-3=-4(x+2) and passee through the point (-5,7

netineya [11]

Answer: $y=\frac{1}{4}x+\frac{33}{4}$

Step-by-step explanation:

1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.

2. The equation given in the problem is written in Point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope.

3. Therefore, the slope of its perpendicular line must be:

$m=\frac{1}{4}$

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

$y-7=\frac{1}{4}(x+5)$

5. In slope intercept form is:

$y=\frac{1}{4}x+\frac{5}{4}+7\\y=\frac{1}{4}x+\frac{33}{4}$

7 0

3 years ago

Find the value of x in the Diagram Below.

zhannawk [14.2K]

Answer: x = 12

Step-By-Step: 180 - 100 = 80

Step-By-Step: 80 - 12 = 68

Step-By-Step: 68 is angle ( X + 12)

68 + 12 = 80 + 100 equals 180

6 0

3 years ago

What is the value of x? Round to the nearest tenth. Please Help

Elodia [21]

Answer:

<h2>x = 6.5 cm</h2>

Step-by-step explanation:

The segment 20.2 cm is the tangent. Therefore x and 20.2cm are perpendicular.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=x,\ leg=20.2cm,\ hypotenuse=(14.7+x)cm$

Substitute:

$x^2+20.2^2=(14.7+x)^2$ <em>use (a + b)² = a² + 2ab + b²</em>

$x^2+408.04=14.7^2+(2)(14.7)(x)+x^2$ <em>subtract x² from both sides</em>

$408.04=216.09+29.4x$ <em>subtract 216.09 from both sides</em>

$191.95=29.4x$ <em>divide both sides by 29.4</em>

$x\approx6.5\ cm$

7 0

3 years ago