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Olegator [25]
3 years ago
11

I need help asap! I need help asap! Right answer gets brainlyist

Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

how you like it when you need help on a math problem and someone answers random things Step-by-step explanation:

KengaRu [80]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Math help please! Ty!
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I need help with letters B and C
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3 years ago
Explain how to estimate 368+231 two different ways
Ann [662]
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6 0
4 years ago
A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b
nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

p = 0.1

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}

0.04\sqrt{n} = 0.588

\sqrt{n} = \frac{0.588}{0.04}

\sqrt{n} = 14.7

(\sqrt{n})^{2} = (14.7)^{2}

n = 216

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0
4 years ago
0.75(4x + 2) = 5 - (x + 1.5)<br> X =
djverab [1.8K]

Answer:

The answer is x=1/2 or x=0.5

7 0
3 years ago
Read 2 more answers
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