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masya89 [10]
2 years ago
7

The graph of a linear function passes through points A(-2, 5) and B(4, -4). What is the rate of change of the graph?

Mathematics
1 answer:
rodikova [14]2 years ago
7 0

When using the the slope formula the equation would be

-4-5= -9

4- -2=6

You divide and u get 1.5 which is also known as 1 and 1/2

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Well he buys two books at a bookstore. He spent $44.52 after 6% sales tax is applied, but the clerk does not provide him with th
mart [117]

Let x represent the cost of book B

Book A: $17.50

Book B: x

Sales tax: (A + B) x 6% = .06(17.50 + x) = 1.05 + .06x

book A + book B + sales tax = total cost

(17.50) + (x) + (1.05 + .06x) = 44.52 <em>plugged in all of the values</em>

18.55 + 1.06x = 44.52 <em>added like terms</em>

1.06x = 25.97 <em>subtracted 18.55 from both sides</em>

x = 24.50 divided 1.06 from both sides

Answer: $24.50

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3 years ago
7/6 * 16/6 in simplest form​
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3.83333333333

Step-by-step explanation:

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3 years ago
1.
cluponka [151]

Answer:

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Step-by-step explanation:

Tbh

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3 years ago
A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0
3 years ago
What is the maximum of f(x)= sin(x)?<br><br> -2π<br> -1<br> 1<br> 2π
nadezda [96]

Answer:

1

Step-by-step explanation:

the maximum of f(X)=sin(X) is 1

6 0
2 years ago
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