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Ulleksa [173]
3 years ago
10

Help thanks for brainliest btw

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:

b and and think 4

Step-by-step explanation:

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Raul drove 80 miles. This represents 50% of his entire trip. What is the total number of miles in Raul's trip?
Dafna11 [192]
If 80 miles is 50% of his trip, then you know that 80 miles is only HALF of his entire trip. To get the distance Raul traveled in total, simply double the 80 miles. This would be 160 miles. 
Raul traveled a total of 160 miles in his trip.
7 0
4 years ago
Please help me how to figure this out I’m trying to figure out the area ASAP please
Natasha2012 [34]

Answer:

1230.88m^{2}

Step-by-step explanation:

Shown is one-fourth of a circle. Also, according to the picture, the radius is 28 meters.

The area for a whole circle is 2\pi r^{2}.

Using that information, we can find the area as if the circle was whole instead of just the fourth.

2(\pi)(28m)^2 = 2(3.14)(784m^{2} ) = 4923.52m^{2}

Now that we know the area of the whole circle, we just have to divide it by four to find the area of the fourth of the circle.

4923.52m^{2}  / 4 = 1230.88m^{2}

That means that the area of the shape shown is 1230.88m^{2}.

I hope this helps!

4 0
3 years ago
Square of (1\4A+1\4B)^2
miskamm [114]

Answer:4a = 2⋅(2a)⋅1 4 a = 2 ⋅ ( 2 a) ⋅ 1

Step-by-step explanation:

Factor 4a^2-4a+1. 4a2 − 4a + 1 4 a 2 - 4 a + 1. Rewrite 4a2 4 a 2 as (2a)2 ( 2 a) 2. (2a)2 − 4a+1 ( 2 a) 2 - 4 a + 1. Rewrite 1 1 as 12 1 2. (2a)2 − 4a+12 ( 2 a) 2 - 4 a + 1 2. Check that the middle term is two times the product of the numbers being squared in the first term and third term. 4a = 2⋅(2a)⋅1 4 a = 2 ⋅ ( 2 a) ⋅ 1.

7 0
3 years ago
g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

4 0
3 years ago
A pink paint mixture uses 4 cups of white paint for every 3 cups of red paint.
Flura [38]

Answer:

cant see the table

Step-by-step explanation:

3 0
3 years ago
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