The area of a rectangle is x^2-4/2x in.^2 and its length is (x+2)^2/2 in. What is the width in inches?

Determine if converges or diverges. Show steps

Brut [27]

(3^x-2)/9^x=1/3^x-2/9^x
which converges by thereom
it converges to 10/72=5/36
id show work if i could but take my word,
if u cant solve it try working out a few partial sums

6 0

3 years ago

Plzz hel am timed which number is composite

mezya [45]

15 is compostit bevuasw (3x5=15) (1x15)

8 0

3 years ago

Read 2 more answers

Please help me with math thanks

Korvikt [17]

Given that a room is shaped like a golden rectangle, and the length is 29 ft with the ratio of golden rectangle being (1+√5):2, thus the width of the room will be:
ratio of golden triangle=(length if the room)/(width of the room)
let the width be x
thus plugging the values in the expression we get:
29/x=(1+√5)/2
solving for x we get:
x/29=2/(1+√5)
thus
x=(29×2)/(1+√5)
answer is:
x=58/(1+√5)
or
byrationalizing the denominator by multiplying both the numerator and the denominator by (1-√5)
58/(1+√5)×(1-√5)/(1-√5)
=[58(1-√5)]/1-5
=(58√5-58)/4

7 0

3 years ago

Solve for x.

Lana71 [14]

Answer:

B. -5

Step-by-step explanation:

this is quite simple, so what you are going to want to do is multiply -3 by 4, and -16, so distribute that and you'll end up with

-12x+48= -12

then you want to subtract 48 from both side to leave the x on one side alone

that will be -12x= -60

after that you have to divide both sides by -12 to find your x

so then you will see that your x is = -5! hope this helps!!

4 0

3 years ago

I need help with this

andre [41]

Answer:

$f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}$

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

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Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

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Taken altogether, these factors give us the function ...

$\boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}$

8 0

3 years ago