What is 3 times the sum of x plus 2 is less than 10 as an inequality?

7. The dimensions of a lawn shaped like a trapezoid are given in meters.

Veronika [31]

Answer:D:102

Step-by-step explanation:

6 0

2 years ago

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(-2,3) is one vertex of a square on a coordinate plane. Name three points that could be the other vertices.

wariber [46]

Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square

Hope that helps :)

3 0

2 years ago

PPPLEASE HELP<br><br> do the problem

Serggg [28]

Step-by-step explanation:

1. No: angles add to more than 180 deg.

2. Yes: each side's length is between the sum and difference of the lengths of the other two sides.

3. No: not every side's length is between the sum and difference of the lengths of the other two sides.

4. Yes: for example, place the 50 deg angle between the two given sides. Another side will then make the triangle.

5. Yes: for example, use 3 cm as the short leg in a 30-60-90 right triangle.

3 0

2 years ago

No clue what to do for slope , where do i put it ?!!!

Nonamiya [84]

You put the point at (5,0) since it’s rise over run you move 3 up n go 4 to the right

3 0

3 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

3 years ago