Which are examples of unit rates? Check all that apply.
1 answer:
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Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).
Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²
Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3
Answer:
Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²
Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3
Answer:
Answer:
1) Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
2) First four terms are: 2,5,8,11
3) First four terms are: 8,13,20,29
4) First four terms are: 0,0,2,6
5) First four terms are: 0,1,1.41,1.73
Step-by-step explanation:
1.
n 1 2 3 4 5 6
f(n) 12 24 36 48 60 72
Domain: { 1,2,3,4,5,6}
Range: {12,24,36,48,60,72}
Write first four terms of each sequence
2) f(n)=3n-1
Put n = 1, 3(1)-1 = 3-1 = 2
Put n = 2, 3(2)-1 = 6-1 = 5
Put n = 3, 3(3)-1 = 9-1 = 8
Put n = 4, 3(4)-1 = 12-1 = 11
So, First four terms are: 2,5,8,11
3) f(n)=n^2+2n+5
Put n = 1, (1)^2+2(1)+5= 1+2+5 = 8
Put n = 2, (2)^2+2(2)+5 = 4+4+5= 13
Put n = 3, (3)^2+2(3)+5 = 9+6+5 = 20
Put n = 4, (4)^2+2(4)+5 = 16+8+5 = 29
So, First four terms are: 8,13,20,29
4) f(n)=(n-1)(n-2)
Put n = 1, (1-1)(1-2) = 0(-1) = 0
Put n = 2, (2-1)(2-2) = 1(0) = 0
Put n = 3, (3-1)(3-2) = 2(1) = 2
Put n = 4, (4-1)(4-2) = 3(2) = 6
So, First four terms are: 0,0,2,6
5) f(n) =
Put n=1
Put n=2
Put n=3
Put n=4
So, First four terms are: 0,1,1.41,1.73