Answer:
a. 0.9 Hz b. 0.37 Hz
Step-by-step explanation:
The frequency of the simple pendulum f = (1/2π)√g/l where g = acceleration due to gravity and l = length of pendulum
a. Find the frequency of a pendulum whose length is 1 foot and where the gravitational field is approximately 32 ft/s2
To find f on Earth, g = 32 ft/s² and l = 1 ft
So, f = (1/2π)√(g/l)
f = (1/2π)√(32 ft/s²/1 ft)
f = (1/2π)√(32/s²)
f = (1/2π)(5.66 Hz)
f = 0.9 Hz
b. The strength of the gravitational field on the moon is about 1/6 as strong as on Earth.. Find the frequency of the same pendulum on the moon.
On the moon when acceleration due to gravity g' = g/6,
f = (1/2π)√(g'/l)
f = (1/2π)√(g/6l)
f = (1/2π)√[32 ft/s²/(6 × 1 ft)]
f = (1/2π)√(32/s²)/√6
f = (1/2π)(5.66 Hz)/√6
f = 0.9/√6 Hz
f = 0.37 Hz
Answer:
the answer is 50cm
Step-by-step explanation:
x=5
so 5+5 would be 10
so the long side would be 10 and the short side would be 5
so 5cmx10cm= 50cm
The answer is a. to be a function there can’t be an x value that is the same to a different y value. so as an example (6,7) (3,2) (5,6) (6,3) is not a function because 6 appears 2 times as an x value but with different y values. but you can have the same y value.
A nonagon has 9 sides
The formula for the sum of all the interior angles of a polygon is 180(n-2) where n is the # of sides. Then the answer is:
180*(9-2)
180 * 7
1260 is the answer
Answer:
5/14
Step-by-step explanation:
I added up all of the numbers and then put it over 20 and divided it down to get the lowest answer possible
