All categories

3 years ago

Find the length of the missing side

Mathematics

2 answers:

timurjin [86]3 years ago

7 0

Answer:

Step-by-step explanation:

Mkey [24]3 years ago

6 0

Answer:

it should be 40 in.

Step-by-step explanation:

because you have to use pythagorean theorem which is A square plus B square equals C square

Hope it helps.

You might be interested in

What are the angle measurements of 6x + 1° = 3x + 11°

hodyreva [135]

Answer:

$x=3\frac{1}{3}^\°$

Step-by-step explanation:

Given equation:

$6x+1\°=3x+11\°$

To find the angle measure of $x$

Solution:

In order to find the angle measure $x$ , we will isolate $x$ on left side by carrying out math operations on both sides.

We have:

$6x+1\°=3x+11\°$

Subtracting both sides by $3x$

$6x-3x+1\°=3x-3x+11\°$

$3x+1\°=11\°$

Subtracting both sides by 1°.

$3x+1\°-1\°=11\°-1\°$

$3x=10\°$

Dividing both sides by 3.

$\frac{3x}{3}=\frac{10\°}{3}$

$x=\frac{10}3}^\°$

Converting fraction to mixed number by dividing and writing the quotient as whole number and the remainder as numerator.

∴ $x=3\frac{1}{3}^\°$ (Answer)

7 0

3 years ago

What is the answer to 3y-3=15+2y

Jobisdone [24]

Answer:

y=18

Step-by-step explanation:

3y-3=15+2y

3y-3+3=15+2y+3

3y=2y+18

3y-2y=2y+18-2y

y=18

I hope this helps!

3 0

4 years ago

Anita took 1/6 of a cake and Barry took 60% of what remained. What fraction of original cake is left. Explain full method.

Sedaia [141]

The cake = 1
1-1/6=5/6
60% as a fraction =3/5
5/6-3/5
25/30-18/30
7/30
There are 7/30 of the original cake left.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Help please!! Write the equation of the line fully simplified slope-intercept form.

Kisachek [45]

Answer:

y=mxtb right? so... y= 0+8

Step-by-step explanation:

i think so right? im sorry if im wrong

4 0

3 years ago

Suppose the coefficient matrix of a linear system of four equations in four variables has a pivot in each column. Explain why th

Veseljchak [2.6K]

If the coefficient matrix has a pivot in each column, it means that it is shaped like this:

$A=\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]$

So, the correspondant system

$Ax = b$

will look like this:

$\left[\begin{array}{cccc}a_{1,1}&a_{1,2}&a_{1,3}&a_{1,4}\\0&a_{2,2}&a_{2,3}&a_{2,4}\\0&0&a_{3,3}&a_{3,4}\\0&0&0&a_{4,4}\end{array}\right]\cdot \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] = \left[\begin{array}{c}b_1\\b_2\\b_3\\b_4\end{array}\right]$

This turn into the following system of equations:

$\begin{cases}a_{1,1}x_1+a_{1,2}x_2+a_{1,3}x_3+a_{1,4}x_4=b_1\\a_{2,2}x_2+a_{2,3}x_3+a_{2,4}x_4=b_2\\a_{3,3}x_3+a_{3,4}x_4=b_3\\a_{4,4}x_4=b_4\end{cases}$

The last equation is solvable for $x_4$ : we easily have

$x_4=\dfrac{b_4}{a_{4,4}}$

Once the value for $x_4$ is known, we can solve the third equation for $x_3$ :

$x_3 = \dfrac{b_3-a_{3,4}x_4}{a_{3,3}}$

(recall that $x_4$ is now known)

The pattern should be clear: you can use the last equation to solve for $x_4$ . Once it is known, the third equation involves the only variable $x_3$ . Once

4 0

4 years ago