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8_murik_8 [283]
3 years ago
15

Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p

roperty you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

a. Quotient property of logarithms, P = log[(d + 1)/d]

b.  log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

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For the given functions f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.
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The domain for (a) , (b) , (c) is all set of real numbers , for (d) (x ε R except x = 3/8.

The complete question is

a) (f + g)(x), (b) (f – g)(x), (c) (f × g)(x), (d) (f / g)(x), (e) (f + g)(7), (f) (f - g)(2), (g) (f.g)(3), (h) (f/g)(27)

<h3>What is a Function ?</h3>

A function is the law that defines the relation between independent and a dependent variable.

It is given that

f(x) = 3x+8

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(a)  (f + g)(x) = 3x+8 +8x-3 = 11x+5

(b)  (f – g)(x) = 3x+8 -8x+3 = -5x +11

(c) (f × g)(x) = (3x+8)(8x-3) = 24x²-9x+64x -24 = 24x² +55x-24

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(e) (f + g)(7) = 11*7+5 = 77+5 = 82

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(g) (f.g)(3) =24*9 +55*3 -24 = 357

(h)  (f/g)(27) = (3x+8)/(8x-3)  = (3 * 27 +8)/(8*27-3) = 89/213

The domain for (a) , (b) , (c) is all set of real numbers , for (d) (x ε R except x = 3/8)

To know more about Function

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