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8_murik_8 [283]
3 years ago
15

Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p

roperty you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

a. Quotient property of logarithms, P = log[(d + 1)/d]

b.  log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

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Answer: 76.28 approximately 76

Step-by-step explanation:

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