Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p
roperty you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit
1 answer:
Answer:
a. Quotient property of logarithms, P = log[(d + 1)/d]
b. log2 = 0.301
Step-by-step explanation:
a. State with property you would use to rewrite the expression as a single logarithm.
I would use the Quotient property of logarithms, which states that
logA - logB = log(A/B)
So, P = log(d+1) - log(d) = log[(d + 1)/d]
b. What is the probability that the number 1 is the leading digit
Since d = 1,
P = log[(d + 1)/d]
= log[(1 + 1)/1]
= log(2/1)
= log2
= 0.301
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