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8_murik_8 [283]

2 years ago

15

Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p

roperty you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit

1 answer:

ludmilkaskok [199]2 years ago

8 0

Answer:

a. Quotient property of logarithms, P = log[(d + 1)/d]

b. log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

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A square pyramid. The square base has side lengths of 6 inches. The 4 triangular sides have a base of 6 inches and height of 9 i

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Answer:

The area of the pyramid’s base is 36 in².

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Step-by-step explanation:

"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.

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To calculate the <u>area of the base</u>, use the formula for area of a square.

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$A_{base} = (6 in)^{2}$

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Harrizon [31]

Answer:

The answer is

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Step-by-step explanation:

$f(x) = 25x - 3$

To find the inverse of f(x) , equate f(x) to y

That's

y = f(x)

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Next interchange the terms that's x becomes y and y becomes x

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We have the final answer as

${f}^{ - 1} (x) = \frac{x +3 }{25}$

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