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8_murik_8 [283]
2 years ago
15

Bedford's law states that the probability that a number in a set has a given leading digit d, is P=log(d+1)-log(d), state with p

roperty you would use to rewrite the expression as a single logarithm. WHAT IS THE PROBABILITY that the number 1 is the leading digit
Mathematics
1 answer:
ludmilkaskok [199]2 years ago
8 0

Answer:

a. Quotient property of logarithms, P = log[(d + 1)/d]

b.  log2 = 0.301

Step-by-step explanation:

a. State with property you would use to rewrite the expression as a single logarithm.

I would use the Quotient property of logarithms, which states that

logA - logB = log(A/B)

So, P = log(d+1) - log(d) = log[(d + 1)/d]

b. What is the probability that the number 1 is the leading digit

Since d = 1,

P = log[(d + 1)/d]

= log[(1 + 1)/1]

= log(2/1)

= log2

= 0.301

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Answers:

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Reason 11: Vertical Angles Theorem

Reason 12: Vertical Angles Theorem

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Explanations:

Reason 4: Triangle DCE is an isosceles triangle because of statement 1 of the proof table. The congruent base angles lead to congruent opposite sides.

Reason 5 and 6: This is the idea of breaking any segment into smaller pieces. The smaller pieces glue back together to get the larger original segment.

Reasons 7 and 8: Substitution is a math term which means "replacement". So for instance, in line 7 we started with DB = DC + CB (from line 6), then we replaced the "DB" with "DF" (see line 3); and then replaced "DF" with "DE+EF"

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REQUIRED:

Round to 3 decimal placed the value of the irrational number e.

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