19 points..................

A distribution of probabilities for random outcomes of a bivariate or dichotomous random variable is called a Group of answer ch

slega [8]

A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.

<h3>What is a binomial probability distribution?</h3>

The binomial distribution with parameters n and p in probability theory and statistics is the discrete probability distribution of the number of successes in a succession of n separate experiments, each asking a yes-no question and each with its own Boolean-valued outcome: success or failure.

The binomial distribution is widely used to describe the number of successes in a sample of size n selected from a population of size N with replacement.
If the sampling is done without replacement, the draws are not independent, and the resulting distribution is hypergeometric rather than binomial.
Binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.

As the description itself says, binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.

Therefore, a distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.

Know more about binomial probability distribution here:

brainly.com/question/9325204

#SPJ4

Complete question:

A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called a ______.

Group of answer choices

(A) binomial probability distribution

(B) distribution of expected values

(C) random variable distribution

(D) mathematical expectation

5 0

2 years ago

Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o

Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

$c = coffee\\ j= juice\\ d = doughnut$

So, we have:

Anna

$2c + j + 2d = 7.50$

Barry

$c + 3d = 5.00$

Cathy

$3c + j + 4d = 11.50$

Required

The price of each

We have:

$2c + j + 2d = 7.50$

$c + 3d = 5.00$

$3c + j + 4d = 11.50$

Make c the subject in: $c + 3d = 5.00$

$c = 5.00 - 3d$

Substitute $c = 5.00 - 3d$ in $2c + j + 2d = 7.50$ and $3c + j + 4d = 11.50$

$2c + j + 2d = 7.50$

$2[5.00 - 3d] + j + 2d = 7.50$

$10.00 - 6d+ j + 2d = 7.50$

Make j the subject

$j = 7.50 - 10.0 +6d - 2d$

$j = -2.50 +4d$

$3c + j + 4d = 11.50$

$3[5.00 - 3d] + j + 4d = 11.50$

$15.00 - 9d + j + 4d = 11.50$

Make j the subject

$j = 11.50 - 15.00 + 9d -4d$

$j = -3.50 + 5d$

So, we have:

$j = -3.50 + 5d$ and $j = -2.50 +4d$

Equate both values of j

$-3.50 + 5d = -2.50 + 4d$

Collect like terms

$5d - 4d = 3.50 -2.50$

$d = 1.00$

Substitute $d = 1.00$ in $j = -3.50 + 5d$

$j = -3.50 + 5d$

$j = -3.50 + 5 * 1.00$

$j = -3.50 + 5.00$

$j = 1.50$

To solve for c, we substitute $d = 1.00$ in $c + 3d = 5.00$

$c + 3 * 1.00 =5.00$

$c + 3.00 =5.00$

Solve for c

$c =- 3.00 +5.00$

$c =2.00$

7 0

2 years ago

Simplity 2(- 4)+7(x + 2).

Evgesh-ka [11]

Answer:

Step-by-step explanation:

To find your answer you first have to multiply the numbers that aren’t in parentheses and you multiply 2 and 7 and you get 14 then you don’t have to worry about the x because it is a variable so now add -4 +2. but first we have to turn negative into positive so you add -4 + 8

7 0

3 years ago

Just makes a punch that is 1/4 cranberry juice which two fractions are equivalent to 1/4

viva [34]

2/8 and 4/16 are equivalent to 1/4

6 0

3 years ago

Read 2 more answers

The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o

frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 36, \sigma = 5$

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40 - 36}{5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0

3 years ago